ffmepg解码的帧存储在哪里？

Question

I try to decode video and convert frame to rgb32 or gb565le format.

Then pass this frame from C to Android buffer by JNI.

So far, I know to how pass buffer from C to Android as well as how to decode video and get decoded frame.

My question is how to convert decoded frame to rgb32 (or rgb565le) and where is it stored?

The following is my code, I'm not sure is correct or not.

-Jargo

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img_convert_ctx = sws_getContext(pCodecCtx->width, pCodecCtx->height, pCodecCtx->pix_fmt, 100, 100, PIX_FMT_RGB32, SWS_BICUBIC, NULL, NULL, NULL);
if(!img_convert_ctx) return -6;

while(av_read_frame(pFormatCtx, &packet) >= 0) {
   // Is this a packet from the video stream?
   if(packet.stream_index == videoStream) {
       avcodec_decode_video2(pCodecCtx, pFrame, &frameFinished, &packet);

       // Did we get a video frame?
       if(frameFinished) {
            AVPicture pict;

            if(avpicture_alloc(&pict, PIX_FMT_RGB32, 100, 100) >= 0) {
                sws_scale(img_convert_ctx, (const uint8_t * const *)pFrame->data, pFrame->linesize, 0, pCodecCtx->height, pict.data, pict.linesize);
            }
       } // End of if( frameFinished )
   } // End of if( packet.stream_index == videoStream )

   // Free the packet that was allocated by av_read_frame
   av_free_packet(&packet);
}

Answer 1

The decoded frame goes into pict . ( pFrame is a raw frame.)

100x100 is probably no good you have to calculate pict size based on pFrame size. I guess it should be pFrame->width*pFrame->height*32;

You have to allocate pict yourself.

See this tutorial http://dranger.com/ffmpeg/