MySQL不同行的总和

Question

I have a query performing INNER JOINs pulling in a relational cross reference table. So based on the query, I'm getting all (one to many) 'fruits' related to a basket. I need to sum the amount of fruits distinctly.

| Banana | 1 |
| Banana | 1 |
| Apple  | 1 |
| Pear   | 1 |
| Pear   | 1 |
| Pear   | 1 |

I want the result set to look like this...

| Banana | 2 | 
| Apple  | 1 |
| Pear   | 3 |

I tried to SUM() fruit in the SELECT with a GROUP BY but the results were not correct (way off). I'm thinking HAVING might need to come into play... anyway, frustrated since this should be pretty easy.

Answer 1

If there are only 1's in the second column, try:

SELECT fruit, count(fruit)
FROM fruits_table
GROUP BY fruit

Answer 2

Not too difficult with a SUM() and GROUP BY:

select a.fruit, sum(a.num) as number
from fruits a
group by a.fruit;

SQLFiddle: http://sqlfiddle.com/#!2/3b53a/1

Answer 3

Try this code:

select fruit_name, sum(qte) 
from fruit_table_name
group by fruit_name;