[英]MYSQL Select Distinct with SUM
I am developing a Stocks management application, the Portfolio register table has 4 columns, other than date and registry_key, and it looks like this: 我正在开发一个Stocks管理应用程序,Portfolio寄存器表有4列,除了date和Registry_key之外,它看起来像这样:
----------------------------------------
| stock_key | user_key | units | price |
----------------------------------------
| fund_a | user_1 | 1000 | 100.35|
| fund_c | user_2 | 4000 | 101.55|
| fund_d | user_3 | 2000 | 105.65|
| fund_a | user_1 | 1500 | 101.45|
| fund_b | user_1 | 500 | 103.35|
----------------------------------------
I wish to select the portfolio of user_1 with distinct stock_key. 我希望选择具有不同stock_key的user_1的投资组合。 For example:
例如:
For user_1 the result should be: 对于user_1,结果应为:
[
{fund_key: "fund_a", units: sum(1000,1500), price: sum(100.35,101.45)},
{fund_key: "fund_b", units: 500, price: 103.35}
]
Hope the question is understandable. 希望这个问题是可以理解的。 Thanks.
谢谢。
Second Phase 第二阶段
How about I need the price as the aggregate total paid over the number of units. 我需要价格作为支付的总数超过单位数量的价格。 So for user_1 the result would be like:
因此,对于user_1来说,结果将是:
[
{fund_key: "fund_a", units: sum(1000,1500), price: sum(1000*100.35,1500*101.45)/sum(1000,1500)},
{fund_key: "fund_b", units: 500, price: 103.35}
]
This is important because once the user has brought more units of the same stock at a lower/higher price than before, the accumulated stocks price is averaged out. 这很重要,因为一旦用户以比以前更低/更高的价格带来了更多单位的相同股票,则累计股票价格将被平均。
Thanks. 谢谢。
So try: 因此,请尝试:
SELECT stock_key, SUM(units), SUM(units * price) / SUM(units)
FROM Portfolio
WHERE user_key = 'user_1'
GROUP BY stock_key;
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