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使用参数的索引器构建表达式树

[英]Building Expression Tree Using a Parameter's Indexer

Given a class that has a property that is a Dictionary 给定一个类,该类的属性为Dictionary

public class Product
{
    public Dictionary<string, string> Attributes { get { return attributes; } }

    private Dictionary<string, string> attributes = new Dictionary<string, string>();
}

I want to be able to match products in a list of products based on criteria that are retrieved from a data store that are in the format of 我希望能够根据从数据存储中检索到的格式为的格式匹配产品列表中的产品

Brand == Tyco
Color != Blue

My current approach is to construct an expression from the filter, and then pass that expression as the parameter to a LINQ Where method call like so 我当前的方法是从过滤器构造一个表达式,然后将该表达式作为参数传递给LINQ Where方法调用,如下所示

products = products.Where(myConstructedExpression);

where myConstructedExpression would normally be a lamda expression that looks like 其中myConstructedExpression通常是一个lamda表达式,看起来像

p => p.Attributes[attribute] == value

I have assembled the following code for testing purposes, but it always fails the call to lambda.Compile() regardless of what I have tried for he left expression. 我已经为测试目的汇编了以下代码,但是无论我为他留下的表达式尝试了什么,它始终无法调用lambda.Compile()

Dictionary<string, ExpressionType> expressionType = new Dictionary<string, ExpressionType>();
expressionType.Add("==", ExpressionType.Equal);
expressionType.Add("!=", ExpressionType.NotEqual);

string filter = "Brand == Tyco";
string[] fields = filter.Split(' ');
string attribute = fields[0];
string op = fields[1];
string value = fields[2];

Product product = new Product();
product.Attributes.Add("Brand", "Tyco"); 

var parameter = Expression.Parameter(typeof(Product), "p");
var left = /***** THIS IS WHAT I AM FAILING TO CONSTRUCT PROPERLY ********/
var right = Expression.Constant(value);
var operation = Expression.MakeBinary(expressionType[op], left, right);
var lambda = Expression.Lambda<Func<Product, bool>>(operation, parameter);

var result = lambda.Compile()(product);

Questions 问题

  1. Is this even a reasonable approach, and, if so, 这是否是一种合理的方法?如果是,
  2. How do I construct the left expression? 如何构造左表达式?

So to get p => p.Attributes["Brand"] <someoperator> "Tyco" , you can do this. 因此,要获得p => p.Attributes["Brand"] <someoperator> "Tyco" ,您可以执行此操作。

The "trick", to work with indexed types, is to use their Item property (you could also work with the get_item method) 使用索引类型的“技巧”是使用其Item属性(您也可以使用get_item方法)

var parameter = Expression.Parameter(typeof(Product), "p");
Expression left = Expression.Property(parameter, "Attributes");
left = Expression.Property(left, "Item", new Expression[] { Expression.Constant(attribute) });

EDIT 编辑

the version with the IDictionary.ContainsKey(<value>) test 使用IDictionary.ContainsKey(<value>)测试的版本

really step by step, but I think this makes things clearer at first. 确实是一步一步来的,但是我认为这首先会使事情变得更清楚。

//left part of lambda, p
var parameter = Expression.Parameter(typeof(Product), "p");
//right part
//p.Attributes
Expression left = Expression.Property(parameter, "Attributes");

var method = typeof(IDictionary<string, string>).GetMethod("ContainsKey");
//p.Attributes.ContainsKey("Brand");
Expression containsExpression = Expression.Call(left, method, Expression.Constant(attribute));
//p.Attributes.Item["Brand"]
Expression keyExpression= Expression.Property(left, "Item", new Expression[] { Expression.Constant(attribute) });
//"Tyco"
var right = Expression.Constant(value);
//{p => IIF(p.Attributes.ContainsKey("Brand"), (p.Attributes.Item["Brand"] == "Tyco"), False)}
Expression operation = Expression.Condition(
                           containsExpression,
                           Expression.MakeBinary(expressionType[op], keyExpression, right), 
                           Expression.Constant(false));
var lambda = Expression.Lambda<Func<Product, bool>>(operation, parameter);

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