为什么递归在不同的递归调用位置上有不同的作用

Question

I'm trying to understand how recursion works. I have two codes that have different outputs due to the placement of the recursive call. I understand that it's SUPPOSED to have different outputs, but I don't understand WHY the output is what it is.

Code 1 (recursive call placed AFTER print):

public class Test {
    public static void main(String[] args) {
        xMethod(5);
    }

    public static void xMethod(int n) {
        if (n > 0) {
            System.out.print(n + " ");
            xMethod(n - 1);
        }
    }
}

The above output is 5 4 3 2 1. I understand why I get this output. It's because first, 5 is printed, then 5 is deducted by 1 and 4 is printed, and so on.

What is I don't understand is the output of the following code, when the recursive call is place before the print.

Code 2 (recursive call placed before print):

public class Test {
    public static void main(String[] args) {
        xMethod(5);
    }

    public static void xMethod(int n) {
        if (n > 0) {
            xMethod(n - 1);
            System.out.print(n + " ");
        }
    }
}

The above output is 1 2 3 4 5. I can't figure out why I get this output. I would imagine the output to be 4 3 2 1, as the 5 is deducted, then printed as 4, and so on. But this obviously is not the case.

Can someone help me understand what is going on in the recursive process?

Answer 1

In first case printing is done and then call happens.

In second case calls happens in this way :

x(5) -> x(4) -> x(3) -> x(2) -> x(1) -> print(1) ->print(2) ->print(3) ->print(4) -> print(5)

Printing starts from the end call.

x(5)
  |
  x(4)                            print(5)
    |                             | 
    x(3)                    print(4)
      |                     |
      x(2)            print(3)
        |             |
        x(1)    print(2)
          |     | 
          print(1)  

In case of first

  print(5)
  x(5)
  |
  print(4)
  x(4)                            
    |
    print(3)                             
    x(3)                    
      |
      print(2)                     
      x(2)            
        | 
        print(1)  
        x(1)    

Answer 2

In the second code the line: System.out.print(n + " "); will not be executed unless all the recursive calls get completed.

The recursive function is calling itself before executing the print line.

Answer 3

In the first script,

public static void xMethod(int n) {
    if (n > 0) {
        System.out.print(n + " ");
        xMethod(n - 1);
    }
}

The output is printed before the step into the recursive call.

In the second script,

public static void xMethod(int n) {
    if (n > 0) {
        xMethod(n - 1);
        System.out.print(n + " ");
    }
}

The function keeps stepping "into" the recursion ie once xMethod(n-1) is called, the line below it is not executed ie the print statement. And this keeps happening until the last recursive call has been executed ie when x == 1, then the call goes backward and starts all the print statements beginning with the print statement for x == 1, then the print statement for x == 2 etc until the last print statement for the first call.

Answer 4

I have listed a stack trace of your second snippet's execution flow (Wish I could have aligned the table and 4 columns better)

If you step through your program when debugging it, you will obtain to a similar stack trace that tells you the value of the variables as you step through the program's execution flow, tabulated similar to the info listed below:

Stack trace| Value of Variable n | Statement executed | Output

main
    xmethod(5)          5               xmethod(4)
     xmethod(4)         4               xmethod(3)
      xmethod(3)        3               xmethod(2)
       xmethod(2)       2               xmethod(1)
        xmethod(1)      1               xmethod(0)
         xmethod(0)     0               
        xmethod(1)      1            System.out.print(1 + " ")                1
       xmethod(2)       2            System.out.print(2 + " ")                1 2
      xmethod(3)        3            System.out.print(3 + " ")                1 2 3
     xmethod(4)         4            System.out.print(4 + " ")                1 2 3 4
    xmethod(5)          5            System.out.print(5 + " ")                1 2 3 4 5

You should go through this tutorial( http://www.vogella.com/articles/EclipseDebugging/article.html ) to get the hang of debugging. Debugging a program will help you to get a head-start to resolve queries like this one, yourself.