[英]Recursion does not take place even after recursive call
Even though the function is recurssive in nature it never recurse.即使函数本质上是递归的,它也永远不会递归。 I am completely blank why this is happening.我完全空白为什么会发生这种情况。
public void fill(Graphics g, View v, Point interior, Color boundaryColor, Color interiorColor) {
int x = interior.getx();
int y = interior.gety();
System.out.println("x: "+x+" y: "+y);
int pixelColor = v.getPixel(x, y);//always negative or zero
if( pixelColor == 0) {
System.out.println("Exit case");
return;
}
if( (pixelColor != boundaryColor.getRGB()) && (pixelColor != interiorColor.getRGB())) {
System.out.println("*");
interior.drawPoint(g, v);
int nextX, nextY;
nextX = x+1;
nextY = y;
Point p= new Point(v, nextX, nextY);
this.fill(g, v, p, boundaryColor, interiorColor);
}
}
Explanation: View v, Graphics g and Point interior are custom objects;说明:View v、Graphics g 和Point internal 是自定义对象;
If the function has been recursive in nature it might have printed "Exit Case when the exit case is reached"如果函数本质上是递归的,它可能会打印“到达退出案例时退出案例”
Code execution results:代码执行结果:
Your function is recursing just fine as shown by the output it produces.您的函数递归得很好,如它产生的输出所示。 What it isn't doing is printing "Exit case" because pixelColor
is never 0. Debug your code/print the values of pixelColor
and try to find out why it's never 0.它没有做的是打印“退出案例”,因为pixelColor
永远不会为 0。调试您的代码/打印pixelColor
的值并尝试找出为什么它永远不会为 0。
变量pixelColor似乎没有达到 0 这就是为什么你的代码没有打印“退出案例”
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