从字符串中提取十六进制数

Question

I want to extract hexadecimal number from a string. For example, the string is: OxDB52 Message 1 of orderid 1504505254 for number +447123456789 rejected by Operator . I want to extract hexadecimal OxDB52 part. I know it can be done checking for 0x in string.

But is there any cool pythonic way to extract hexadecimal number from string?

Answer 1

You can use regex pattern with re.findall() method:

re.findall(r'0x[0-9A-F]+', your_string, re.I)

this will give you a list of all the hexadecimal numbers in your_string .

Demo:

>>> s = '0xDB52 Message 0x124A orderid 1504505254 for number 0xae45'
>>> re.findall(r'0x[0-9A-F]+', s, re.I)
['0xDB52', '0x124A', '0xae45']

Answer 2

假设单词被正确分开

[x for x in my_string.split() if x.startswith('0x')]