如何将一组十六进制数字作为字符串？

Question

I want to compute the key of round 10 based another key , It works very well if ikk is a string, so how to convert it into a string?

def test():
    ##### ikk=  '000102030405060708090a0b0c0d0e0f'  ===> It works!!!
    ikk= 000102030405060708090a0b0c0d0e0f
    ik=str(ikk)
    data = [re.findall('..', item) for item in key.split('\n')]
    for item in data:
        if item:
            result = [int(x, 16) for x in item]
            print(result)
            result = keyScheduleRounds(result, 0, 10)
            tt=''.join(["%02x"%d for d in result])
            print(tt)

Error that I found:

ik= str(000102030405060708090a0b0c0d0e0f)                              ^
SyntaxError: invalid token

Answer 1

If ikk is an hexadecimal number (and it looks like), try this way : ikk = 0x000102030405060708090a0b0c0d0e0f . Notice the 0x at the beginning that will tell python this is an hexadecimal number, and not a decimal number.

Answer 2

set ik :

ik= bytearray.fromhex("000102030405060708090a0b0c0d0e0f").decode()

This will convert hexadecimal to string. Full code is written below.

def test():
    ik = bytearray.fromhex("000102030405060708090a0b0c0d0e0f").decode()
    data = [re.findall('..', item) for item in key.split('\n')]
    for item in data:
        if item:
            result = [int(x, 16) for x in item]
            print(result)
            result = keyScheduleRounds(result, 0, 10)
            tt=''.join(["%02x"%d for d in result])
            print(tt)