将char num [50]复制到std :: string

Question

How to copy contents of char array to std::string (not conversion)

Ex :

void CApp::ChangeState(GameState* state)
{
std::string strImagePath;
// cleanup the current state
if ( !states.empty() ) {
    states.back()->Clean();
    states.pop_back();
    //states.back()->getImagePath( psImagepath );
}

// store and init the new state
states.push_back(state);
states.back()->Init();

//psImagepath = (char*)malloc(sizeof(char)*50);
states.back()->getImagePath( psImagepath );

printf("MenuState Init path %s\n",psImagepath);

}

i want to copy my contents into strImagePath (consider strImage path is declared in class definition)

Answer 1

Just use the string's constructor that takes a char array :

char arr[50];
//Fill your array, do stuff, etc, etc
<...>
std::string str(arr);

Note that the char array that you are passing to the constructor should be null-terminated.

Answer 2

您可以使用strImagePath.append(charArray)要追加的char []，或strImagePath.assign(charArray)以取代以前的内容strImagePath通过的char []的内容。

Answer 3

使用构造函数（ std::string(const char* str) ）或复制赋值运算符（ std::string& operator=(const char* str) ）。