MongoDB Map减少新手（PHP）

Question

I'm new to the map reduce concept and even though I'm making some slow progress, I'm finding some issues that I need some help with.

I have a simple collection consisting of an id, city and and destination, something like this:

{ "_id" : "5230e7e00000000000000000", "city" : "Boston", "to" : "Chicago" },
{ "_id" : "523fe7e00000000000000000", "city" : "New York", "to" : "Miami" },
{ "_id" : "5240e1e00000000000000000", "city" : "Boston", "to" : "Miami" },
{ "_id" : "536fe4e00000000000000000", "city" : "Washington D.C.", "to" : "Boston" },
{ "_id" : "53ffe7e00000000000000000", "city" : "New York", "to" : "Boston" },
{ "_id" : "5740e1e00000000000000000", "city" : "Boston", "to" : "Miami" },
...

(Please do note that this data is just made up for example purposes)

I'd like to group by city the destinations including a count:

{ "city" : "Boston", values : [{"Chicago",1}, {"Miami",2}] }
{ "city" : "New York", values : [{"Miami",1}, {"Boston",1}] }
{ "city" : "Washington D.C.", values : [{"Boston", 1}] }

For this I'm starting to playing with this function to map:

    function() {
        emit(this.city, this.to);
    }

which performs the expected grouping. My reduce function is this:

    function(key, values) {
        var reduced = {"to":[]};

        for (var i in values) {
            var item = values[i];
            reduced.to.push(item);
        }

        return reduced;
    }

which gives somewhat an expected output:

{ "_id" : ObjectId("522f8a9181f01e671a853adb"), "value" : { "to" : [    "Boston", "Miami" ] } }
{ "_id" : ObjectId("522f933a81f01e671a853ade"), "value" : { "to" : [  "Chicago",  "Miami", "Miami" ] } }
{ "_id" : ObjectId("5231f0ed81f01e671a853ae0"), "value" : "Boston" }

As you can see, I still haven't counted the repeated cities, but as can be seen above, for some reason the last result in the output doesn't look good. I'd expected it to be

{ "_id" : ObjectId("5231f0ed81f01e671a853ae0"), "value" : { "to" : ["Boston"] } }

Has this anything to do with the fact that there is a single item? Is there any way to obtain this?

Thank you.

Answer 1

I see you are asking about a PHP issue, but you are using javascript to ask, so I'm assuming a javascript answer will help you move things along. As such here is the javascript needed in the shell to run your aggregation. I strong suggest getting your aggregation working in the shell(or some other javascript editor) in general and then translating it into the language of your choice. It is a lot easier to see what is going on and there faster using this method. You can then run:

use admin
db.runCommand( { setParameter: 1, logLevel: 2 } )

to check the bson output of your selected language vs what the shell looks like. This will appear in the terminal if mongo is in the foreground, otherwise you'll have ot look in the logs.

Summing the routes in the aggregation framework [AF] with Mongo is fairly strait forward. The AF is faster and easier to use then map reduce[MR]. Though in this case they both have similar issues, simply pushing to an array won't yield a count in and of itself (in MR you either need more logic in your reduce function or to use a finalize function).

With the AF using the example data provided this pipeline is useful:

db.agg1.aggregate([
     {$group:{
         _id: { city: "$city", to: "$to" },  
         count: { $sum: 1 }
     }},
     {$group: {
         _id: "$_id.city",
         to:{ $push: {to: "$_id.to", count: "$count"}}
     }}
]);

The aggregation framework can only operate on known fields, but many pipeline operations so a problem needs to broken down with that as a consideration. Above, the 1st stage calculates the numbers need, for which there are 3 fixed fields: the source, the destination, and the count. The second stage has 2 fixed fields, one of which is an array, which is only being pushed to (all the data for the final form is there).

For MR you can do this:

var map = function() {
    var key = {source:this.city, dest:this.to};
    emit(key, 1);
};

var reduce = function(key, values) {
    return Array.sum(values);
};

A separate function will have to pretty it however.

If you have any additional questions please don't hesitate to ask.

Best, Charlie