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Question

i have a dialog window that have to containers and two on click listeners to close the dialog and i want i to be displayed just once and i use this code but it doesn't display it at all!!

any help?

  SharedPreferences setting = getSharedPreferences("dialogprefs", 0); final SharedPreferences.Editor editor = setting.edit(); { final Dialog dialog = new Dialog(this); dialog.requestWindowFeature(Window.FEATURE_NO_TITLE); dialog.getWindow().setBackgroundDrawable(new ColorDrawable(android.graphics.Color.TRANSPARENT)); dialog.setContentView(R.layout.hint1); dialog.setCanceledOnTouchOutside(true); dialog.setTitle("Hint"); View masterView = dialog.findViewById(R.id.LinearLayout1); masterView.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { dialog.dismiss(); editor.putString("dialogshow", "0".toString()); editor.commit(); } }); View masterView1 = dialog.findViewById(R.id.imageView1); masterView1.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { dialog.dismiss(); editor.putString("dialogshow", "0".toString()); editor.commit(); } }); if (setting.getString("dialogshow" , "0").equals("0")) { dialog.dismiss(); } else { dialog.show(); } } 

Answer 1

Assuming that setting.getString("dialogShow", "0") means something like getString(name, defaultValue) then the default is "0" if the preference hasn't been set yet, which means the dialog will never be shown even once. Perhaps you mean setting.getString("dialogShow", "1") .