从常规xpath获取精确的xpath

Question

I need to do 2 thing.

1. Verify a value of a node in a XML file.

2. If the value correspond, I need to change it.

   I already have a complex hierarchy of object that do this job. Now I'm facing a problematic case. Lets look at an example:

    <staticTag> <randomTag> <anotherRandomTag> <staticTag property="id"> <staticTag> VALUE </staticTag> </staticTag> </anotherRandomTag> </randomTag> </staticTag> 

This happen n time in each XMLFile I have to parse. It would be easy with

//staticTag[@property='id']/staticTag/text()

Yes it will return to me all the value i need to verify. The problem is I don't have the precise xpath to change the value if it correspond to the value I am looking for.

I may post sample of code if necessary. So tl;dr : Is there a way to generate precise xpath from a general one? As usual thank you for your time.

I have done a few more testHere is a dummy xml

<tag>
   <ZDSJG>
      <SJROT>X66P1</SJROT>
   </ZDSJG>
   <DNLVZ>
      <SJROT>VV1EZ</SJROT>
   </DNLVZ>
</tag>

My Xpath xpression that I am looking for is //SJROT With a function i wrote I can generate this XPATH from the first node : /#document/tag/ZDSJG/SJROT/#text

Unfortunately the xpath expression //SJROT don't return me the second node that have this name. Here a snippet of code that look for the Xpath expression provided

    XPathExpression expression = xpath.compile(expressionXPath);

    NodeList result = (NodeList) expression.evaluate(document, XPathConstants.NODE);

    List<String> generatedXpath = Lists.newArrayList();
    for (int i = 0; i < result.getLength(); i++) {
        generatedXpath.add(getXPath(result.item(i)));
    }
    return generatedXpath;

Another edit: I fixed my code, I had to use NODESET instead of NODE Will no try to generate the proper Xpath

Answer 1

Since I have not found anything that would generate me the XPath from a node. I did my own. It is pretty basic and could be improve in so many ways. But at the moment it fit my needs. If anybody have a better solution I will gladly accept it. Here is my java code: feel free to improve it

    public List<String> generateAbsoluteXpath(File fileToRead, String expressionXPath) throws Exception {
    DocumentBuilderFactory documentFactory = DocumentBuilderFactory.newInstance();
    Document document = documentFactory.newDocumentBuilder().parse(fileToRead);

    XPathFactory xpathFactory = XPathFactory.newInstance();
    XPath xpath = xpathFactory.newXPath();

    XPathExpression expression = xpath.compile(expressionXPath);
    NodeList result = (NodeList) expression.evaluate(document, XPathConstants.NODESET);

    List<String> generatedXpath = Lists.newArrayList();
    for (int i = 0; i < result.getLength(); i++) {
        generatedXpath.add(getXPath(result.item(i)));
    }
    return generatedXpath;
}



public String getXPath(Node node)
{
    Node parent = node.getParentNode();
    if (parent == null || parent.getNodeName().equals("#document")) {
        return "/" + node.getNodeName();
    }
    return getXPath(parent) + "/" + node.getNodeName();
}

So Basically, I input an XPath that will generate multiple node. It return me the list of absolute xpath referencing the node that were found with the general path. Since i have the absolute xpath the other object I am working with may now read / replace the value. Problem solved.