[英]Pattern matching syntax alternative to chains of _=:=typeOf[_] tests in Scala macros
Is there already a pattern match alternative for writing long winded tests like 是否已经有一种模式匹配替代方法可以编写冗长的测试,例如
if (aTpe =:= typeOf[Int]) 1
else if (aTpe =:= typeOf[Long]) 2
else if (aTpe =:= typeOf[Double]) 3
else ...
perhaps something that looks a little like 也许看起来有点像
aTpe match {
case tpe[Int] => 1
case tpe[Long] => 2
case tpe[Doble] => 3
...
}
It looks pretty easy to write an extractor for this, but I want to find out if there isn't already something like this. 为此编写一个提取器看起来很容易,但是我想知道是否还没有这样的东西。
What I've been doing in normal code so far is materialized types. 到目前为止,我在普通代码中一直在做的是物化类型。 I guess it could be used in macros as well:
我猜它也可以在宏中使用:
val ClassOfInt = classOf[Int]
val ClassOfLong = classOf[Long]
aTpe match {
case ClassOfInt => 1
case ClassOfLong => 2
}
It works but I'd very much like to know if there's a 'terser' way of doing so. 它可以工作,但是我非常想知道是否有一种“更短的”方式。
Of course it is possible to write your if-else-chain nearly the same way with a pattern match and guards: 当然,可以使用模式匹配和保护以几乎相同的方式编写if-else-chain:
scala> import scala.reflect.runtime.universe._
import scala.reflect.runtime.universe._
scala> def f[A : TypeTag] = typeOf[A] match {
case t if t =:= typeOf[Int] => 1
case t if t =:= typeOf[Long] => 2
case _ => 0
}
f: [A](implicit evidence$1: reflect.runtime.universe.TypeTag[A])Int
scala> f[Int]
res5: Int = 1
scala> f[String]
res6: Int = 0
However a construct like case tpe[Int] =>
as shown in your question is not possible because of this ticket: SI-884 - it is just an unimplemented feature. 但是,由于此票证,因此无法像问题中所示的
case tpe[Int] =>
那样构造case tpe[Int] =>
: SI-884-这只是一个未实现的功能。
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