¿如果另一个相关表中不存在该记录，如何避免分页中的记录？ CAKEPHP

Question

I have a doubt doing pagination in CakePHP.

Well, I will try to be concise.

I have three tables, one table is which I paginate (1st table), another table (2nd table) dependent of this one (1st table have FK to 2nd table), and the most important, 3rd table, that has FK to 1st table. So: 3rd table-> 1st table-> 2nd table. I do pagination of 1st table (model) from his controller, so far everything ok, the pagination list all the records from table bd and no problems.

I need also to get records from 1st table but ordering by a record from 2nd table. No problem. The problem IS : I WANT not to get in pagination, records from 1st table (which i paginate it) that arent present in 3rd table.

The problem is that CAKEPHP first make a query getting records from 1st table + 2nd table. After this, it get the records from 3rd table according to the records (PK) obtained from the first query, so I cant say it: not take records from 1st table that arent present in 3rd table.

¿How can I do this?

I hope I explained.

Thank you very much.

Regards.

Answer 1

what you'll want to use is a Counter Cache. Go to http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html and search for 'counterCache,' and you'll find instructions.

Basically, you want to implement a "counter cache" field in model 1, that automatically keeps count of the number of linked records in model 3. Then, to exclude records from Model 1 that have no related records in Model 3, you just add a pagination condition to say that the counter cache field must be greater than 0.

UPDATE:

If you can't use CakePHP's counter cache, then you should emulate the behaviour of the counter cache using a virtual field - see http://book.cakephp.org/2.0/en/models/virtual-fields.html