字节数组到十六进制字符串

Question

I have data stored in a byte array. How can I convert this data into a hex string?

Example of my byte array:

array_alpha = [ 133, 53, 234, 241 ]

Answer 1

Using str.format :

>>> array_alpha = [ 133, 53, 234, 241 ]
>>> print ''.join('{:02x}'.format(x) for x in array_alpha)
8535eaf1

or using format

>>> print ''.join(format(x, '02x') for x in array_alpha)
8535eaf1

Note: In the format statements, the 02 means it will pad with up to 2 leading 0 s if necessary. This is important since [0x1, 0x1, 0x1] ie (0x010101) would be formatted to "111" instead of "010101"

or usingbytearray withbinascii.hexlify :

>>> import binascii
>>> binascii.hexlify(bytearray(array_alpha))
'8535eaf1'

---

Here is a benchmark of above methods in Python 3.6.1:

from timeit import timeit
import binascii

number = 10000

def using_str_format() -> str:
    return "".join("{:02x}".format(x) for x in test_obj)

def using_format() -> str:
    return "".join(format(x, "02x") for x in test_obj)

def using_hexlify() -> str:
    return binascii.hexlify(bytearray(test_obj)).decode('ascii')

def do_test():
    print("Testing with {}-byte {}:".format(len(test_obj), test_obj.__class__.__name__))
    if using_str_format() != using_format() != using_hexlify():
        raise RuntimeError("Results are not the same")

    print("Using str.format       -> " + str(timeit(using_str_format, number=number)))
    print("Using format           -> " + str(timeit(using_format, number=number)))
    print("Using binascii.hexlify -> " + str(timeit(using_hexlify, number=number)))

test_obj = bytes([i for i in range(255)])
do_test()

test_obj = bytearray([i for i in range(255)])
do_test()

Result:

Testing with 255-byte bytes:
Using str.format       -> 1.459474583090427
Using format           -> 1.5809937679100738
Using binascii.hexlify -> 0.014521426401399307
Testing with 255-byte bytearray:
Using str.format       -> 1.443447684109402
Using format           -> 1.5608712609513171
Using binascii.hexlify -> 0.014114164661833684

Methods using format do provide additional formatting options, as example separating numbers with spaces " ".join , commas ", ".join , upper-case printing "{:02X}".format(x) / format(x, "02X") , etc., but at a cost of great performance impact.

Answer 2

Consider the hex() method of the bytes type on Python 3.5 and up:

>>> array_alpha = [ 133, 53, 234, 241 ]
>>> print(bytes(array_alpha).hex())
8535eaf1

EDIT: it's also much faster than hexlify (modified @falsetru's benchmarks above)

from timeit import timeit
N = 10000
print("bytearray + hexlify ->", timeit(
    'binascii.hexlify(data).decode("ascii")',
    setup='import binascii; data = bytearray(range(255))',
    number=N,
))
print("byte + hex          ->", timeit(
    'data.hex()',
    setup='data = bytes(range(255))',
    number=N,
))

Result:

bytearray + hexlify -> 0.011218150997592602
byte + hex          -> 0.005952142993919551

Answer 3

hex_string = "".join("%02x" % b for b in array_alpha)

Answer 4

If you have a numpy array, you can do the following:

>>> import numpy as np
>>> a = np.array([133, 53, 234, 241])
>>> a.astype(np.uint8).data.hex()
'8535eaf1'

Answer 5

Or, if you are a fan of functional programming:

>>> a = [133, 53, 234, 241]
>>> "".join(map(lambda b: format(b, "02x"), a))
8535eaf1
>>>