python，字符串到十六进制数组

Question

fast question, I want this (of course python3):

frame = "AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA"

to this:

frame = [0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA, 0x5, 0x5, 0x5, 0xA, 0xA, 0xA]

Answer 1

We can try this:

frame = "AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA"
[int(character, 16) for character in frame]
# [10, 10, 10, 5, 5, 5, 10, 10, 10, 5, ... ]

As @Reti43 notes in a comment , hexadecimal values like 0xA correspond to numbers like 10, so that's why the resulting list has integers.

If the OP desires hexadecimal, string representation can be used as below. This string can then be passed to int to get the corresponding integer.

frame = "AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA555AAA"
[f"0x{character}" for character in frame]
# ['0xA', '0xA', '0xA', '0x5', '0x5', '0x5', '0xA', '0xA', '0xA', '0x5', ...]