PHP代码将图像格式更改为JPG

Question

I constructed this PHP code to use ImageMagick to convert gif files to jpg but it doesn't seem to work. Maybe I am missing something:

<?php
$cwd = getcwd();
$directory = 'temp_images/input/'; // add path to the source direcotry, reprocesses all images directly, not fancy.

$dh = opendir($directory);

while($file = readdir($dh)) {
  if (strlen($file) > 2) {
    $dirfiles[]=$file;
  }
}
closedir($dh);
reset($dirfiles);
asort($dirfiles);


set_time_limit(0);
foreach ($dirfiles as $dirfile) {
  $file = $directory.$dirfile;
  $cmd = 'mogrify -format jpg *.gif $file';     
  echo  $dirfile . " mogrified to JPG \n";
}

?>

The gif files are not being converted.

UPDATE: In my own code I replaced with $cmd = 'mogrify -format jpg *.gif $file'; to exec("mogrify -format jpg . $file");

I was under the impression when I use mogrify the original files are purged. How do I go about it?

Answer 1

$cmd永远不会执行...它只是一个字符串值。

Answer 2

You are using the wrong type of 'quotes'

foreach ($dirfiles as $dirfile) {
  $file = $directory.$dirfile;
  $cmd = 'mogrify -format jpg *.gif $file';     
  echo  $dirfile . " mogrified to JPG \n";
}

You want the back-tick operator .

foreach ($dirfiles as $dirfile) {
  $file = $directory.$dirfile;
  $cmdResult = `mogrify -format jpg *.gif $file`;     
  echo  $dirfile . " mogrified to JPG \n";
}

This is identical to using shell_exec .

foreach ($dirfiles as $dirfile) {
  $file = $directory.$dirfile;
  $cmdResult = shell_exec ( "mogrify -format jpg *.gif {$file}" );     
  echo  $dirfile . " mogrified to JPG \n";
}