[英]How do I get the date difference as a floating-point number with millisecond precision
public static void main(String[] args) throws InterruptedException{
long sTime = new Date().getTime();
Thread.sleep(3234);
long eTime = new Date().getTime();
float diff = ((eTime-sTime)/1000);
System.out.println(diff);
}
In the above code, I am expecting the output to be 3.234 but it is 3.0. 在上面的代码中,我期望输出为3.234但它是3.0。 I want the exact difference between two times in seconds, with a fractional part.
我希望在几秒钟内两次之间有确切的差异,并有一个小数部分。
You are doing an integral division instead of a floating-point one. 您正在执行积分除法而不是浮点除法。 Try this:
尝试这个:
float diff = ((float)(eTime-sTime)/1000.0);
As you are using long
s, I further suggest you to use double
datatype for greater precision: 当您使用
long
,我进一步建议您使用double
数据类型以提高精度:
double diff = ((double)(eTime-sTime)/1000.0);
double sTime = new Date().getTime();
Thread.sleep(3234);
double eTime = new Date().getTime();
double diff = ((eTime-sTime)/1000);
System.out.println(diff);
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