如何以毫秒精度獲取日期差作為浮點數

Question

public static void main(String[] args) throws InterruptedException{
    long sTime =  new Date().getTime();
    Thread.sleep(3234);
    long eTime =  new Date().getTime();
    float diff = ((eTime-sTime)/1000);
    System.out.println(diff);
}

在上面的代碼中，我期望輸出為3.234但它是3.0。 我希望在幾秒鍾內兩次之間有確切的差異，並有一個小數部分。

Answer 1

您正在執行積分除法而不是浮點除法。 嘗試這個：

float diff = ((float)(eTime-sTime)/1000.0);

當您使用long ，我進一步建議您使用double數據類型以提高精度：

double diff = ((double)(eTime-sTime)/1000.0);

Answer 2

    double sTime =  new Date().getTime();
    Thread.sleep(3234);
    double eTime =  new Date().getTime();
    double diff = ((eTime-sTime)/1000);
    System.out.println(diff);