[英]How to make hollow box using two for loops
Use nested for loops statements to draw hallow boxes of "*"s.使用嵌套的 for 循环语句来绘制由“*”组成的空盒子。 The boxes have the same number of rows and columns and this number should be input from the user (valid range: 5 to 21).
这些框具有相同的行数和列数,并且该数字应由用户输入(有效范围:5 到 21)。 I'm having trouble coming up with a way to make the box hollow.
我很难想出一种使盒子空心的方法。 this is what i have for the code and it comes as a complete square, but i need it to be hollow or just the border.
这就是我的代码,它是一个完整的正方形,但我需要它是空心的或只是边框。
System.out.println("How many rows/columns(5-21)?");
rows=input.nextInt();
while(rows<5||rows>21){
System.out.println("Out of range. Reenter: ");
rows=input.nextInt();
}
for(m=1;m<=rows;m++){
for(c=1;c<=rows;c++){
System.out.print("*");
}
System.out.println();
}
You need to print only some of the *<\/code> s, so add a test before the
print("*")<\/code> .
您只需要打印一些
*<\/code> s,因此在
print("*")<\/code>之前添加一个测试。
One option would be to explicitly test the four conditions (top, bottom, left, right) and OR them together logically:
一种选择是显式测试四个条件(顶部、底部、左侧、右侧)并将它们逻辑地 OR 在一起:
if( (m==1) || //top
(m==rows) || //bottom
(c==1) || //left
(c==rows) //right
) {
System.out.print("*");
} else {
System.out.print(" ");
}
import java.util.Scanner;
public class icibos {
public static void main(String[] args) {
Scanner gir = new Scanner(System.in);
System.out.print("Karenin kenarını girin: ");
int kenar = gir.nextInt();
for (int i = 1; i <= kenar; i++) {
for (int j = 1; j <= kenar; j++) {
if (i == 1 || i == kenar || j == 1 || j == kenar)
System.out.print("*");
else
System.out.print(" ");
}
System.out.println();
}
}
}
for (int i=1;i<=lgh;i++){
for (int a=1;a<=lgh;a++){
if(i>1 && i<lgh && a>1 && a<lgh)
System.out.print(" ");
else
System.out.print("*");
}
System.out.println("");
}
Try this , its bit hard code.<\/strong>试试这个,它有点硬代码。<\/strong>
Working Example here<\/a>
这里的<\/a>工作示例
String myStars="*******";
String oneStar="*";
int count=0;
System.out.println(myStars);
count++;
while(count<=7)
{
System.out.println(oneStar+" "+oneStar);
count++;
}
System.out.print(myStars);
You can try this你可以试试这个
Example is Here<\/a>示例在
这里<\/a>
String pattern;
int noOfTimes;
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the pattern to print : ");
pattern = scanner.nextLine();
System.out.print("Enter number of times it should get printed : ");
noOfTimes = scanner.nextInt();
for(int i=1; i<=noOfTimes; i++) {
System.out.println();
if(i==1 || i==noOfTimes) {
for(int j=1; j<=noOfTimes; j++){
System.out.print(pattern+" ");
}
}
else {
for(int k=1; k<=noOfTimes;k++) {
if(k==1 || k == noOfTimes) {
System.out.print(pattern + " ");
}
else {
System.out.print(" ");
}
}
}
}
import java.util.Scanner;
public class holsqr{
public static void main(String args[]){
Scanner ma=new Scanner(System.in);
System.out.print("Enter the number:");
int max=ma.nextInt();
for(int i=1;i<=max;i++){
for(int j=1;j<=max;j++){
if((i==1)||(i==max)){
System.out.print("#");
}else{
if(j==1||j==max){
System.out.print("#");
}
else{
System.out.print(" ");
}
}
}
System.out.println();
}
}
}
It pretty simple, using two while loop: public static void main(String[] args) {很简单,使用两个 while 循环: public static void main(String[] args) {
int size = 0;
int r = 0;
String star = "*";
String space = " ";
System.out.print("Input size of side of square: ");
Scanner input = new Scanner(System.in);
size = input.nextInt();
while (r < size) {
int c = 0;
while (c < size) {
System.out.print(r > 0 && r < size - 1 && c > 0 && c < size - 1 ? space : star);
++c;
}
System.out.println();
++r;
}
}
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