StringTokenizer问题

Question

I am facing some problems in String tokenizer like if I code is following then there are some questions which I want to know.

Code :

public class Str_Tokenizer {
    public static void main(String args[]){
        StringTokenizer st=new StringTokenizer("this is him");
        while(st.hasMoreTokens()) {
            System.out.println(st.nextToken());
        }
    }
}

Questions:

1. If I don't use the while(st.hasMoreTokens()) then how I can use StringTokenizer ?
2. If I don't use st.nextToken , what I should use?

Answer 1

StringTokenizer is a legacy class that is retained for compatibility reasons

First you cannot use that class without those hasMoreTokens() and next() method.

You cannot loop on it as a alternative because hasMoreElements() Returns the same value as the hasMoreTokens method. nextElement() Returns the same value as the nextToken method and you don't want to use them.

other wise hasMoreElements and nextElement are alternatives.

Although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

Even docs of StringTokenizer given example how you can avoid to use it

The following example illustrates how the String.split method can be used to break up a string into its basic tokens:

 String[] result = "this is a test".split("\\s");
 for (int x=0; x<result.length; x++)
     System.out.println(result[x]);

Answer 2

If you don't want to use while and nextToken , go for String split. this way:

String s ="this is him";
        String[] s2 = s.split(" ");
        for (String str : s2) {
            System.out.println(str);
        }