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matlab中的多变量梯度下降

[英]Multi variable gradient descent in matlab

I'm doing gradient descent in matlab for mutiple variables, and the code is not getting the expected thetas I got with the normal eq. 我在matlab中为多个变量做渐变下降,并且代码没有达到我用正常eq得到的预期值。 that are: theta = 1.0e+05 * 3.4041 1.1063 -0.0665 With the Normal eq. 即:theta = 1.0e + 05 * 3.4041 1.1063 -0.0665使用Normal eq。 I have implemented. 我已经实施了。

And with the GDM the results I get are: theta = 1.0e+05 * 2.6618 -2.6718 -0.5954 And I don't understand why is this, maybe some one can help me and tell me where is the mistake in the code. 而对于GDM我得到的结果是:theta = 1.0e + 05 * 2.6618 -2.6718 -0.5954我不明白为什么会这样,也许有人可以帮助我并告诉我代码中的错误在哪里。

Code: 码:

function [theta, J_history] = gradientDescentMulti(X, y, theta, alpha, num_iters)

m = length(y); % number of training examples
J_history = zeros(num_iters, 1);
thetas = size(theta,1);
features = size(X,2)

mu = mean(X);
sigma = std(X);
mu_size = size(mu);
sigma_size = size(sigma);

%for all iterations
for iter = 1:num_iters

tempo = [];

result = [];

theta_temp = [];

%for all the thetas    
for t = 1:thetas
    %all the examples
    for examples = 1:m
       tempo(examples) = ((theta' * X(examples, :)') - y(examples)) * X(m,t)
    end

    result(t) = sum(tempo)
    tempo = 0;

end

%theta temp, store the temp 
for c = 1:thetas

    theta_temp(c) = theta(c) - alpha * (1/m) * result(c)
end

%simultaneous update
for j = 1:thetas

    theta(j) = theta_temp(j)

end

% Save the cost J in every iteration    
J_history(iter) = computeCostMulti(X, y, theta);

end

theta
end

Thanks. 谢谢。

EDIT: Data. 编辑:数据。

  X =
    1.0000    0.1300   -0.2237
    1.0000   -0.5042   -0.2237
    1.0000    0.5025   -0.2237
    1.0000   -0.7357   -1.5378
    1.0000    1.2575    1.0904
    1.0000   -0.0197    1.0904
    1.0000   -0.5872   -0.2237
    1.0000   -0.7219   -0.2237
    1.0000   -0.7810   -0.2237
    1.0000   -0.6376   -0.2237
    1.0000   -0.0764    1.0904
    1.0000   -0.0009   -0.2237
    1.0000   -0.1393   -0.2237
    1.0000    3.1173    2.4045
    1.0000   -0.9220   -0.2237
    1.0000    0.3766    1.0904
    1.0000   -0.8565   -1.5378
    1.0000   -0.9622   -0.2237
    1.0000    0.7655    1.0904
    1.0000    1.2965    1.0904
    1.0000   -0.2940   -0.2237
    1.0000   -0.1418   -1.5378
    1.0000   -0.4992   -0.2237
    1.0000   -0.0487    1.0904
    1.0000    2.3774   -0.2237
    1.0000   -1.1334   -0.2237
    1.0000   -0.6829   -0.2237
    1.0000    0.6610   -0.2237
    1.0000    0.2508   -0.2237
    1.0000    0.8007   -0.2237
    1.0000   -0.2034   -1.5378
    1.0000   -1.2592   -2.8519
    1.0000    0.0495    1.0904
    1.0000    1.4299   -0.2237
    1.0000   -0.2387    1.0904
    1.0000   -0.7093   -0.2237
    1.0000   -0.9584   -0.2237
    1.0000    0.1652    1.0904
    1.0000    2.7864    1.0904
    1.0000    0.2030    1.0904
    1.0000   -0.4237   -1.5378
    1.0000    0.2986   -0.2237
    1.0000    0.7126    1.0904
    1.0000   -1.0075   -0.2237
    1.0000   -1.4454   -1.5378
    1.0000   -0.1871    1.0904
    1.0000   -1.0037   -0.2237

y =
      399900
      329900
      369000
      232000
      539900
      299900
      314900
      198999
      212000
      242500
      239999
      347000
      329999
      699900
      259900
      449900
      299900
      199900
      499998
      599000
      252900
      255000
      242900
      259900
      573900
      249900
      464500
      469000
      475000
      299900
      349900
      169900
      314900
      579900
      285900
      249900
      229900
      345000
      549000
      287000
      368500
      329900
      314000
      299000
      179900
      299900
      239500

Full dataset. 完整数据集。

The line where you calculate tempo is wrong. 计算速度的行是错误的。 It should be 它应该是

tempo(examples) = ((theta' * X(examples, :)') - y(examples)) * X(examples,t)

Also try using matrix operations in MATLAB. 还尝试在MATLAB中使用矩阵运算。 Your code will be faster and it will also be easier to understand. 您的代码会更快,也更容易理解。 For example, you can replace your nested loop with 例如,您可以使用替换嵌套循环

E = X * theta - y;
for t = 1:thetas
    result(t) = sum(E.*X(:,t));
end

You can replace your subsequent two loop for updating theta into one line 您可以替换后续的两个循环以将theta更新为一行

theta = theta - alpha * (1/m) * result';

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