[英]How can i print numbers on single line
Silly doubt, how can i print numbers in sequence in C programming according to its variable value. 愚蠢的疑问,我如何才能按照C变量的可变值顺序打印数字。 my Code 我的密码
#include <stdio.h>
void main()
{
int i,j,result;
for (i=1;i<=4;i++)
{
for (j=i;j<=i;j++)
{
printf("%d\n%d",i,j+1);
}
}
}
getting output as 作为输出
1
22
33
44
Expecting answer is: 期望的答案是:
1
22
333
4444
void main()
{
int i,j,result;
for (i=1;i<=4;i++)
{
for (j=1;j<=i;j++)
{
printf("%d",i);
}
printf("\n");
}
}
It could help you. 它可以帮助您。 Note that in C
array indexing starts at 0, not 1. 请注意,在C
数组中,索引始于0,而不是1。
void main()
{
int i,j;
for (i = 0; i < 4; ++i)
{
for (j = 0; j < i; ++j)
{
printf("%d", i);
}
printf("\n");
}
}
#include <stdio.h>
void main()
{
int i,j,result;
for (i=1;i<=4;i++)
{
for (j=i;j<=i;j++)
{
printf("%d",i);
}
printf("\n");
}
}
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