SQL查询按日期排序

Question

I have a query like

select id, item, date producer from table

The result is like this:

id         item            producer            date
1          apple            A                  2013-10-26
2          pear             A                  2013-10-26
3          peach            A                  2013-10-26
4          orange           B                  2013-10-26
5          strawberry       B                  2013-10-27
6          melon            B                  2013-10-27
7          apple2           A                  2013-10-27
8          orange3          A                  2013-10-27

I need to shuffle these data "order by DATE DESC" and get something like this:

item            producer
orange3          A
melon            B
apple2           A
strawberry       B
pear             A
orange           B
apple            A
peach            A
melon            B

I DON'T want to display like this:

ALL A ITEM... ALL B ITEM... Or shuffle something added today with something added yesterday... In my example I don't want to display "orange" before "orange3"

My solution (but very slow)

Select * from table where date = $date order by rand;
Select * from table where date = $date -1 order by rand;
select * from table where date = $date -2 order by rand;

(This is just a concept, $date cannot be decremented with this method)

Answer 1

See if the following does the trick for you:

SELECT * 
FROM `table` 
ORDER BY `date` DESC, RAND()

I just tried it and it seems to do what I think you want.

Edit

If you want to persist the "shuffle" then add a column of type DOUBLE named rnd , do

UPDATE `table` SET rnd = RAND()

and then in your SELECT statement use

.... ORDER BY `date` DESC, `rnd`