[英]uint8_t* expected a ;
VS10 is underlining uint8_t, saying that it expected a semi-colon. VS10正在强调uint8_t,称它预计会出现分号。
Here's my code snippet:- 这是我的代码片段: -
uint8_t* pixelPtr = (uint8_t*)image.data; //this line shows the error (expected a ;)
Yet, when I use it lower down my code, no errors are attached to it:- 然而,当我使用它降低我的代码时,没有错误附加到它: -
typedef Scalar_<uint8_t> bgrPixel; //this line is error free
Did you forget a ;
你忘了一个
;
on a previous class
or struct
declaration? 在以前的
class
或struct
声明? If so, then it's interpreting uint8_t
as a variable name that is an instance of that struct
or class
. 如果是这样,那么它将
uint8_t
解释为变量名称,该变量名称是该struct
或class
的实例。
For example, if you did this: 例如,如果你这样做:
class clown
{
// yadda
// yadda
...
} // notice no semicolon here
uint8_t *pixelPtr = (uint8_t*)image.data;
The compiler effectively sees: 编译器有效地看到:
class clown
{
// yadda
// yadda
...
} uint8_t *pixelPtr = (uint8_t*)image.data;
and naturally wants a semicolon after uint8_t
, so it looks more like this: 并且在
uint8_t
之后自然想要一个分号,所以它看起来更像是这样的:
class clown
{
// yadda
// yadda
...
} uint8_t; // which would declare an instance of class clown named uint8_t
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