从向量中提取 uint8_t* 子集<uint8_t></uint8_t>

Question

I have a vector<uint8_t> , and I'm interfacing with an api that expects a uint8_t* data, size_t size . I need to provide the api with a subset of my vector, in my current solution I create a subset by using the vector constructor, and then I pass the data() of this new vector to the api:

vector<uint8_t> subset(bytes.begin() + offset, bytes.begin() + offset + size);
api(subset.data(), subset.size());

This works fine in the majority of cases, but it is running out of memory on constrained devices. Is there a more efficient way to extract a uint8_t* subset from a vector<uint8_t> ?

Answer 1

Yes, just combine the two but with data instead of begin .

api(bytes.data() + offset, size);

Using subscript and address-of operators also works

api(&bytes[offset], size);

Answer 2

I Think you dont need to make a subset, pass vector's first element and size to want to take out of it. Make sure this size is less than equal to bytes.size()

api(&bytes[0],size);