SQL MAX日期（不含分组依据）

Question

I have the following table

Location Type     Date
A        TestType 10-10-2013
A        TestType 05-05-2013
A        BestType 06-06-2013
B        TestType 09-09-2013
B        TestType 01-01-2013

I want to return the max date for each location regardless of the type but I must return all 3 columns.

Desired result:

Location Type     Date
A        TestType 10-10-2013
B        TestType 09-09-2013

What would be the best way to do this?

I've looked into using RANK() Over Partition , but can't get it to work properly.

Answer 1

Using row_number() function and partition by location ordering by [date] desc to get the max date for each location.

;with cte as (
   select location, type, [date], 
          row_number() over (partition by location order by [date] desc) rn
   from yourTable
)
select location, type, [date]
from cte
where rn = 1 --<<-- rn = 1 gets the max date for each location.

Fiddle demo

Answer 2

You can do:

SELECT location, MAX(date)
FROM yourTable
GROUP BY location;

EDIT:

If you want to get type with it you can do:

select y.location, y.Type, y.date
from YourTable y
inner join(
    select location, max(date) maxdate
    from YourTable
    group by location
) ss on y.location = ss.location and y.date = ss.maxdate

sqlfiddle demo