RegEx-在特定字符（＃）之后获取所有字符

Question

使用下面的字符串，如何编写正则表达式以删除或单独保存仅出现在#符号后面的字符。

var category = "http://schemas.google.com/g/2005#work"

Answer 1

You can use this regex:

var category = "http://schemas.google.com/g/2005#work";
var hashval = category.replace(/^[^#]*#([\s\S]*)$/, '$1');
//=> work

OR better using String#match:

var hashval = category.match(/#([\s\S]*)$/)[1];
//=> work

Answer 2

The nice way is to let the browser do the heavy lifting.

var category = "http://schemas.google.com/g/2005#work",
    link = document.createElement('a'),
    hash;

link.href = category;

hash = link.hash;

This has your browser create an a element and set the the href property of that element to be category . The browser then parses the URL. The link's hash property is the bit after the # in the URL.

I answered a similar question some time ago, with a more worked-out version of this code.

Answer 3

i think another way, is using a Capture Group :

\#(.*)

In this way, it is possible to create other different groups to capture different elements.

Hope this helps = D