如何在JavaScript中使用正则表达式匹配第n个字符后的所有字符？

Question

I want to match all characters after 8th character. And not include first 8!

I need exactly a regular expression cause a framework (Ace.js) requires a regexp, not a string. So, this is not an option:

var substring = "123456789".substr(5);

Can I match everything after nth character using regex in JavaScript?

Updates: I can't call replace() , substring() etc because I don't have a string. The string is known at run time and I don't have access to it. As I already said above the framework (Ace.js) asks me for a regex.

Answer 1

(?<=^.{8}).* 

will match everything after the 7th position. Matches 89 in 0123456789

or IJKLM in ABCDEFGHIJKLM

etc

Answer 2

console.log("123456789".match(/^.{8}(.*)/)[1])