如何去除不是单词字符的所有字符的Ruby字符串？

Question

How do I strip a string in Ruby of all characters that aren't word characters (az, any digit), replacing them with a blank?

For instance, for the string "not-using-social-media" I want to strip this to "not using social media"

For the string "16 Surprising Small Business Statistics (Infographic)", I want to strip this to "16 Surprising Small Business Statistics Infographic"

Answer 1

This does not use a regex. It replaces everything which is not in "a-zA-Z0-9 " with a space, then squeezes runs of spaces to one space and removes trailing and tailing whitespace.

str = "not-using-social-media 16 Surprising Small Business Statistics (Infographic)"
p str.tr("^a-zA-Z0-9 ", " ").squeeze(" ").strip
#=>"not using social media 16 Surprising Small Business Statistics Infographic"

Answer 2

I would do either:

phrase = '16 Surprising Small Business Statistics (Infographic)'

p phrase.gsub(/[^a-zA-Z0-9]+/, ' ').strip
#=> "16 Surprising Small Business Statistics Infographic"

p phrase.gsub(/[^[:alnum:]]+/, ' ').strip
#=> "16 Surprising Small Business Statistics Infographic"

A couple of notes:

• The + is added so that consecutive non-alphanumeric characters are replaced with a single space.
• The .strip is added on the assumption you do not want the leading/trailing spaces created.
• The regex does not use \\w since that would also include underscores.

Answer 3

Regex is your friend - http://www.ruby-doc.org/core-1.9.3/Regexp.html

This is the bracket expression you'll want - /[[:alpha:]]/

Answer 4

The easiest solution is simply using delete('^') . It deletes everything except for what comes after ^ .

a='hello-world+'

a.delete('^A-Za-z')  #=> 'helloworld'

a='Hello +World'

a.delete('^A-Za-z ') #=> 'Hello World'

a='01234 ABC'
a.delete('^0-9') #=> '01234'