Microsoft Access按汇总排序？

Question

Is there a way to sort by number of open tasks?

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY OpenTaskCount DESC;

When I try this, it prompts for OpenTaskCount in the GUI.

Answer 1

Try this:

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY COUNT(*) DESC;

Answer 2

Either:

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY Count(*) DESC;

or

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY 2 DESC;

should work.