Microsoft Access按汇总排序？

Question

有没有办法按开放任务的数量排序？

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY OpenTaskCount DESC;

当我尝试这个时，它会在GUI中提示OpenTaskCount。

Answer 1

尝试这个：

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY COUNT(*) DESC;

Answer 2

或者：

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY Count(*) DESC;

要么

SELECT Tasks.ClientName, Count(*) AS OpenTaskCount
FROM Tasks
WHERE (((Tasks.Completed)=False))
GROUP BY Tasks.ClientName
ORDER BY 2 DESC;

应该管用。