是否可以有一个套接字同时侦听两个UDP IP，一个是127.0.0.1（同一台机器），而另一台计算机呢？

Question

An eye-tracking application I use utilizes UDP to send packets of data. I made a python socket on the same computer to listen and dump the data into a .txt file. I already have this much working.

A separate application also written in python (what the eye-tracked subject is seeing) is running on a separate computer. Because the eye-tracking application is continuous and sends unnecessary data, so far I've had to manually parse out the instances when the subject is looking at desired stimuli. I did this based on a manually synchronized start of both the stimuli and eye-tracking applications and then digging through the log file.

What I want to do is have the second computer act as a second UDP client, sending a packet of data to the socket on the eye-tracking computer everytime the subject is looking at stimuli (where a marker is inserted into the .txt file previously mentioned). Is it possible to have a socket listening to two IP addresses at one time?

Here's my socket script:

#GT Pocket client program

import datetime
import socket
now = datetime.datetime.now()
filename = 'C:\gazelog_' + now.strftime("%Y_%m_%d_%H_%M") + '.txt'

UDP_IP = '127.0.0.1' # The remote host (in this case our local computer)
UDP_PORT = 6666 # The same port as used by the GT server by default

sock = socket.socket(socket.AF_INET, #internet
                                socket.SOCK_DGRAM) #UDP 

sock.bind( (UDP_IP, UDP_PORT) )

while True:
    data, addr = sock.recvfrom( 1024) #I assume buffer size is 1024 bytes.
    print "Received Message:", data
    with open(filename, "a") as myfile:
    myfile.write(str(data + "\n"))

sock.close()
myfile.close()

EDIT:

@abarnert I was able to bind to the host address on the Ethernet interface and send a message from computer B to computer A, but computer A was no long able to receive packets from itself. When I specified UDP_IP = '0.0.0.0' computer B was no longer able to send data across the Ethernet. When I specified UDP_IP = '' I received the `error: [Errno 10048] Only one usage of each socket address (protocol/network address/port) is normally permitted

This have to do with the script I used on the Computer B to send the data:

import socket

UDP_IP = "169.254.35.231" # this was the host address I was able to send through.
UDP_PORT = 6666
MESSAGE = "Start"

print ("UDP target IP:"), UDP_IP
print ("UDP target port:"), UDP_PORT
print ("message:"), MESSAGE

sock = socket.socket(socket.AF_INET,
                 socket.SOCK_DGRAM) 
sock.sendto(MESSAGE, (UDP_IP, UDP_PORT) )

I didn't know where (or if at all) I needed to specify INADDR_ANY, so I didn't. But I did try once where import socket.INADDR_ANY but got ImportError: No module named INADDR_ANY

Seems like a simple issue based on your response, so I'm not sure where I'm messing up.

EDIT2: I just reread your answer again and understand why socket.INADDR_ANY doesn't work. Please disregard that part of my previous edit

EDIT3: Okay so the reason that I wasn't picking up data when specifying the host IP was that the application I was collecting data from on Computer A was still specified to send to 127.0.0.1. So I figured it out. I am still curious why 0.0.0.0 didn't work though!

Answer 1

No. A socket can only be bound to a single address at a time.*

If there happens to be a single address that handles both things you want, you can use a single socket to listen to it. In this case, the INADDR_ANY host ( 0.0.0.0 ) may be exactly what you're looking for—that will handle any (IPv4) connections on all interfaces, both loopback and otherwise. And even if there is no pre-existing address that does what you want, you may be able to set one up via, eg, an ipfilter-type interface.

But otherwise, you have to create two sockets. Which means you need to either multiplex with something like select , or create two threads.

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In your case, you want to specify a host that can listen to both the local machine, and another machine on the same Ethernet network. You could get your host address on the Ethernet interface and bind that. (Your machine can talk to itself on any of its interfaces.) Usually, getting your address on "whatever interface is the default" works for this too—you'll see code that binds to socket.gethostname() in some places, like the Python Socket Programming HOWTO . But binding to INADDR_ANY is a lot simpler. Unless you want to make sure that machines on certain interfaces can't reach you (which is usually only a problem if you're, eg, building a server intended to live on a firewall's DMZ), you'll usually want to use INADDR_ANY .

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Finally, how do you bind to INADDR_ANY ? The short answer is: just use UDP_IP = '' , or UDP_IP = '0.0.0.0' if you want to be more explicit. Anyone who understands sockets, even if they don't know any Python, will understand what '0.0.0.0' means in server code.(You may wonder why Python doesn't have a constant for this in the socket module, especially when even lower-level languages like C do. The answer is that it does, but it's not really usable.**)

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* Note that being bound to a single address doesn't mean you can only receive packets from a single address; it means you can receive packets from all networks where that single address is reachable. For example, if your machine has a LAN connection, where your address is 10.0.0.100, and a WAN connection, where your address is 8.9.10.11, if you bind 10.0.0.100, you can receive packets from other LAN clients like 10.0.0.201 and 10.0.0.202. But you can't receive packets from WAN clients like 9.10.11.12 as 10.0.0.100.

** In the low-level sockets API, dotted-string addresses like '0.0.0.0' are converted to 32-bit integers like 0 . Python sometimes represents those integers as int s, and sometimes as 4-byte buffers like b'\\0\\0\\0\\0' . Depending on your platform and version, the socket.INADDR_ANY constant can be either 0 or b'\\0\\0\\0\\0' . The bind method will not take 0 , and may not take b'\\0\\0\\0\\0' . And you can't convert to '0.0.0.0' without first checking which form you have, then calling the right functions on it. This is ugly. That's why it's easier to just use '0.0.0.0' .

Answer 2

I believe you can bind a raw socket to an entire interface, but you appear to be using two different interfaces.

It's probably best to use two sockets with select().