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获取错误:浮点异常

[英]Getting the error: floating point exception

I am a novice coder and I am currently working on the Usaco Training problems to improve my skills. 我是新手编码员,目前正在研究Usaco培训问题,以提高技能。 This was my code for "Greedy Gift Givers". 这是我的代码“ Greedy Gift Givers”。 When I submit the code, I get an error that says: Execution error: Your program (`gift1') exited with signal #8 (floating point exception [usually caused by accessing memory out of bounds]). 提交代码时,出现错误消息:执行错误:您的程序('gift1')退出并显示信号#8(浮点异常[通常是由于超出范围访问内存引起的)。 The program ran for 0.000 CPU seconds before the signal. 该程序在发出信号之前已运行0.000 CPU秒。 It used 3504 KB of memory. 它使用了3504 KB的内存。 " I have been looking through my code and trying to fix this error for a while now. Can anyone help? Please don't get angry with me as this is my first time posting, and like I said, I'm brand new to programming. “我一直在仔细阅读我的代码,现在试图纠正此错误已有一段时间了。有人可以帮忙吗?请不要生我的气,因为这是我第一次发帖,就像我说的那样,我是新手编程。

/*
ID: ashton.1
PROG: gift1
LANG: C++
*/

#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main()
{
    ifstream fin ("gift1.in");
    ofstream fout ("gift1.out");

    int initial, account[10], recipients, NP;
    string names[10], giver, receiver;

    fin >> NP;

    for (int k = 0; k < NP; k++)
    {
        fin >> names[k];
        account[k] = 0;
    }

    for (int k = 0; k < NP; k++)
    {
        fin >> giver >> initial >> recipients;

        for (int y = 0; y < NP; y++)
        {
            if( names[y] == giver)
                break;
        }
        account[k] -= initial;
        account[k] += initial  % recipients;

        for (int y = 0; y < recipients; y++)
        {
            fin >> receiver;

            for (int j = 0; j < NP; j++)
            {
                if(names[j] == receiver)
                    break;
            }
            if(recipients != 0)
            {
                for(int x = 0; x < NP; x++)
                {
                    account[x] += (int)initial / recipients;
                }
            }
        }
        fout << names[k] << " " << account[k] << endl;
    }

    return 0;
}   

When you take initial % recipients you could be dividing by zero if there are no recipients. 当您获取初始%收件人时 ,如果没有收件人,则可以除以零。 Add a conditional statement to filter that case out; 添加条件语句以过滤掉这种情况; this is what gives the floating point exception. 这就是浮点异常的原因。

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