[英]Fraction simplifying algorithm, floating point exception error
I am a beginner, and i am working on a C++ program that simlifies fractions, however I am getting this weird statement printed, it does not indicate an error, but it gives me the output "Floating point exception: 8". 我是一个初学者,我正在研究一个模拟分数的C ++程序,但是我得到了这个奇怪的语句,但它并不表示错误,但是却给我输出了“浮点异常:8”。
Here is a snippet of my code(not yet complete), I do not ask for code and would prefer if my homework is not done for me, but I welcome logical suggestions to fix or improve the algorithms. 这是我的代码片段(尚未完成),我不要求代码,而是希望我的作业没有完成,但我欢迎有逻辑的建议来修复或改进算法。
void Fraction::simplify()
{
int i, x = 0, a[100], b[100];
for (i = 0; i <= den; i++)
{
x = num % i;
if (x == 0)
{
b[i] = i;
}
}
}
Thanks a bunch. 谢谢你
x = num % i;
Computes the remaining of dividing num
by i
计算划分的剩余
num
通过i
But i = 0
in the first step, and you cannot devide by zero. 但是在第一步中,
i = 0
,因此您不能将其除以零。
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