[英]CypherResults py2neo get node object
i need to get the id of a node in neo4j using py2neo. 我需要使用py2neo获取neo4j中节点的ID。 using the following query i am getting a cypher result object which contains a record object
使用以下查询,我得到包含记录对象的密码结果对象
table_query = neo4j.CypherQuery(db, "merge (x: Table{name: 'table_param'}) return x")
the contents of the .data method are equal to the following [Record(x=Node('host/db/data/node/31'))] .data方法的内容等于以下[Record(x = Node('host / db / data / node / 31'))]
how can i get the node object 我如何获得节点对象
CypherQuery gives you a CypherResults object if you .execute()
it or an IterableCypherResult object if you .stream()
it. CypherQuery给你一个CypherResults如果你反对
.execute()
或一个IterableCypherResult对象,如果你.stream()
它。
You can then iterate over the result object: 然后,您可以遍历结果对象:
table_query = neo4j.CypherQuery(db, "merge (x: Table{name: 'table_param'}) return x")
results = table_query.execute()
for r in results:
# get the node you return in your query
my_node = r[0]
# get the properties of your node
props = my_node.get_properties()
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.