Py2neo-如何通过节点匹配获取节点ID？

Question

i'm using py2neo and try to get node id by these code and there is no entity["id"], i want to know anyhow to get id of each node. thank you

for rel in matcher.match("SINGLE_NODE"): print("name:", rel["name"]) print("occur:", rel["occur"]) print("pos:", rel["pos"])

Answer 1

Query for the node(s) using their label and, if filtering, a property. Then you return the node ID and anything else desired.

match (n:YourLabel{Property:xxx}) return id(n) as NodeID

You can also query by id

match (n) where id(n)=12 return id(n)