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有没有办法将wxWidget GUI传递给wxThread？

[英]Is there a way to pass the wxWidget GUI to a wxThread?

原文 2013-11-16 13:47:42 5 1 c++/ multithreading/ user-interface/ wxwidgets

I have made a game that uses a game loop. 我制作了一个使用游戏循环的游戏。 Now i am trying to implement a GUI for this game in wxWidgets. 现在，我正在尝试在wxWidgets中为该游戏实现GUI。

The problem is that when I initialize the GUI the control of the program remains on a GUI loop and doesn't go to the game loop. 问题是，当我初始化GUI时，程序的控件仍保留在GUI循环中，而没有进入游戏循环。

So, can i make the GUI run on its own thread? 那么，我可以让GUI在自己的线程上运行吗？

1 个解决方案

You can, but leave all code, which interacts with the GUI on the main thread/EDT (Event Dispatch Thread). 您可以但保留所有与主线程/ EDT（事件调度线程）上的GUI交互的代码。 Concurrent access to GUI elements is not intended by design and will cause problems. 并发访问GUI元素不是设计意图，并且会引起问题。 Instead, put the game loop into a wxThread and fire appropriate events from there. 而是将游戏循环放入wxThread并从那里触发适当的事件。 Those events can then be handled on the EDT to update the GUI or for rendering a frame. 然后可以在EDT上处理这些事件以更新GUI或渲染框架。

Another solution would be, to invoke single iterations of your game loop on the main thread, using wxTimer . 另一个解决方案是使用wxTimer在主线程上调用游戏循环的单个迭代。

Note: 注意：

Throttle the game loop or coalesce the events if necessary. 如有必要，限制游戏循环或合并事件。 wxTimer does perfectly support throttling by frequency and coalescing of update events. wxTimer确实通过频率和更新事件的合并来完美支持节流。 In a separate thread, you'd need to sleep for the remaining time of the desired cycle/iteration time or wait on a semaphore, triggered by the main thread. 在单独的线程中，您需要休眠所需的周期/迭代时间的剩余时间，或者等待由主线程触发的信号量。
Implement access to share data like the game state with a synchronization object like wxMutex . 实现访问权限，以与wxMutex这样的同步对象共享游戏状态之类的wxMutex 。 Preferably, you could instead use std::mutex and std::thread from C++11. 最好改用C ++ 11中的std::mutex和std::thread 。