我正在尝试找出Python中的简单列表加密

Question

So, I have to simulate some sort of encryption protocol. For example, I have list Hey=['Z','A'] I then transform that list into ascii list using ord() command. No big deal. Problem is here. In order to encrypt I enter some shift value that will move the ascii value and then reform it back to a letter. It's all supposed to be capital letters ranging from A to Z, so ascii code ranges from 65 to 90. I've modified shift value, so that even if it's bigger than 26 it's still works fine. However, how do I modify ascii list itself, so that if one element of a list is bigger than 90 it shifts back? I've tried this:

num=[ord(i)+shift for i in hey]
if num[i]>90:
   num[i]=num[i]-26

However, shift will happen only if both (or all) elements of a list are bigger than 90. Is there a way to make that condition affect each element separately? So that if ascii value of one element is bigger than 90 then shift will happen, but another value will be unaffected until it becomes bigger than 90.

Answer 1

I think using the modulo operator % would be better here. This gets the remainder of a division.

Examples:

>>> 10 % 5
0
>>> 10 % 2
0
>>> 10 % 3
1
>>> 10 % 6
4

Using this, you could replace your code with this:

num = [(ord(i) + shift - 65) % 26 + 65 for i in hey]

This also works with large values of shift. Subtracting 26 means that you can still go out of range when shift >= 27 .

Answer 2

num=[(ord(i)+shift) if ord(i) + shift <= 90 else (ord(i)+shift - 26) for i in hey]

尽管我认为您的其他地方有问题...您可能应该总结一下ascii集的开始