我试图弄清楚如何以 2 的幂为循环递增

Question

I'm used to code in C and i'm currently stuck on a for loop in python.
In C the for loop looks something like for(int i, i<=1024,i*=2){} .
I've tried for i in range(1,1024,*2) ,but it seems it doesn't accept *
i'm currently using

Distance = 1
increment = 2
SearchRange = 1024
while Distance<SearchRange:
  Distance *=increment

to achieve similar results, is there anything i can do in one line in python to make it work.
I'm sure I'm missing something very simple.Please help!Thanks!

Answer 1

To do it using while loops:

step = 1
i = 1
while i <= 1024:
    print(i)
    i *=2

Output:

1
2
4
8
16
32
64
128
256
512
1024

Answer 2

In Python, it would be written:

for i in range(1024):
    i*=2

Check out https://wiki.python.org/moin/ForLoop for lots of other examples.

Answer 3

This should work just fine:

>>> for i in range(15) :
...     print 1 << i, 
... 
1 2 4 8 16 32 64 128 256 512 1024 2048 4096 8192 16384
>>> 

Answer 4

A new answer since the question was updated:

iterable_range = [ 2**j for j in range(0,1024) ]
for i in iterable_range:
    print(i)

Using a for loop you supply an iterable from which the value is selected each iteration. Its not like C where index i is modified. So, to achieve the same in Python, you need to create an iterable of all the values.

This produces the desired:

1
2
4
8
16
32
64
128
etc