用PHP中的％20替换href中的空格

Question

i want to replace every space in a link with %20.

<a href="Replace the spaces here">Some text</a>

i want to get This:

<a href="Replace%20the%20spaces%20here">Some text</a>

not this:

<a%20href="Replace%20the%20spaces%20here">Some%20text</a>

How to do this? preg_replace? Solution (because I cant post an answer):

$search= '(href="(.*?)")s';
$replace= '';
$newstring= preg_replace_callback($search,create_function('$treffer','urlencode($treffer[0]);'),$string);

Answer 1

You should use the urlencode() function for the href part.

http://php.net/urlencode

Answer 2

For the note, every modern browser will process the following just fine:

<a href="Replace the spaces here">Some text</a>

If you insist in doing it regardless, and assuming you cannot urlencode() the links before they're output, you need to use either of:

• preg_replace_callback() or
• a DOM parser

Using either will allow you to only apply urlencode() where it's needed.

Answer 3

您可以尝试以下方法：

<a href="<? echo(urlencode("Replace the spaces here")); ?>">Some text</a>