使用PHP将％S中的SPACES替换为％20

Question

I'm looking to replace all instances of spaces in urls with %20. How would I do that with regex?

Thank you!

Answer 1

No need for a regex here, if you just want to replace a piece of string by another: using str_replace() should be more than enough :

$new = str_replace(' ', '%20', $your_string);

But, if you want a bit more than that, and you probably do, if you are working with URLs, you should take a look at the urlencode() function.

Answer 2

Use urlencode() rather than trying to implement your own. Be lazy.

Answer 3

I think you must use rawurlencode() instead urlencode() for your purpose.

sample

$image = 'some images.jpg';
$url   = 'http://example.com/'

With urlencode($str) will result

echo $url.urlencode($image); //http://example.com/some+images.jpg

its not change to %20 at all

but with rawurlencode($image) will produce

echo $url.rawurlencode(basename($image)); //http://example.com/some%20images.jpg

Answer 4

You've got several options how to do this, either:

• urlencode() or rawurlencode() - functions designed to encode URLs for http protocol
• str_replace() - "heavy machinery" string replace
• strtr() - would have better performance than str_replace() when replacing multiple characters
• preg_replace() use regular expressions (perl compatible)

strtr()

Assuming that you want to replace "\\t" and " " with "%20" :

$replace_pairs = array(
  "\t" => '%20',
  " " => '%20',
);
return strtr( $text, $replace_pairs)

preg_replace()

You've got few options here, either replacing just space ~ ~ , again replacing space and tab ~[ \\t]~ or all kinds of spaces ~\\s~ :

return preg_replace( '~\s~', '%20', $text);

Or when you need to replace string like this "\\t \\t \\t \\t" with just one %20 :

return preg_replace( '~\s+~', '%20', $text);

_{I assumed that you really want to use manual string replacement and handle more types of whitespaces such as non breakable space (   )}

Answer 5

    public static function normalizeUrl(string $url) {
        $parts = parse_url($url);
        return $parts['scheme'] .
            '://' .
            $parts['host'] .
            implode('/', array_map('rawurlencode', explode('/', $parts['path'])));

    }

Answer 6

$result = preg_replace('/ /', '%20', 'your string here');

you may also consider using

$result = urlencode($yourstring)

to escape other special characters as well