pythonic从这个列表中提取字符串的方法

Question

如果我有一个列表['default via 192.168.0.1 dev wlan0 proto static \\n', '192.168.0.0/24 dev wlan0 proto kernel scope link src 192.168.0.11 \\n']什么将是提取192.168.0.1最pythonic的方式192.168.0.1和192.168.0.11

Answer 1

Try this using regular expressions, where lst is the list with the data:

import re
pat = re.compile(r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}[^/]')
[pat.search(s).group(0) for s in lst]
=> ['192.168.0.1', '192.168.0.11']

The above assumes that there's a valid IPv4 IP in each string in the list, and that after the IP there isn't a / character.

Answer 2

«Most pythonic» might be debatable, but something along these lines will work :

fct = lambda e : [w for w in e.split() if '.' in w and '/' not in w][0]
map( fct, l )

> ['192.168.0.1', '192.168.0.11']