使用线程在java中绘制面板

Question

I am writing a program that has a number of different views. One of which is fairly graphics intensive (it displays an interconnected graph). Others just display small but complex diagrams.

I'm finding the paint time for the main view is quite long (even just painting the currently visible area) and while it is being painted, the rest of the interface becomes very slow.

My question is this, can I create a new thread to handle the painting - and if so, will it result in a performance increase, my suspicion is that it wont. I have tried the following:

creating an abstract classs ThreadPaintablePanel, that my complex views inherit from.

public abstract class ThreadPaintablePanel extends JPanel{
 private Thread painter;
 public abstract void paintThread(Graphics g);

 protected void callPaintThread(Graphics g){
   if(painter != null){
     painter.interrupt();
   }
   painter = new Thread(new PaintRunnable(this, g));
   painter.start();
 }
} 

Then in my complicated views my paintComponent method is simply: super.callPaintThread(g);

The overridden paintThread method contains all my painting code. However this results in unpainted panels. Have I missed something obvious?

Thanks

Answer 1

You cannot let any thread but the Event Dispatch Thread (EDT) touch the GUI. Letting other threads mess with the GUI causes trouble and Exceptions. You can employ a multi-threaded multi-buffering technique. It involves two steps:

1. In order to parallelize complicated drawing routines, you can simply divide the entire "view" into patches and let one thread draw one patch into one image. Here is a tutorial on working with images in Java .

2. Once you have the images, you can override paintComponent and use the Graphics.drawImage method to let the EDT display the full or a partial view, by stitching the images of the corresponding patches together.

In order to avoid unnecessary work, make sure to perform the first step initially and then only after the view changed, else just draw previously computed results again. Furthermore, try to only update part of the patches, if you can narrow down the regions inside the views that have changed between frames.

Let us assume that your view is at least as many pixels high as your optimal number of threads, so we can just partition the view vertically. Also, let us assume that drawing any pixel takes about the same amount of work as any other, so we can use the same size for every patch. These two assumptions make things a lot easier.

Code follows. If you don't need your computer to do anything else, you can set nThreads to your number of cores . Note that the code also uses pseudocode for "parallel for" which is explained here :

// let multiple threads write all patches
public BufferedImage[] writePatches(...)
{
    // Given data:
    const int nThreads = ...;         // the amount of threads that you want
    Rectangle viewBox = ...;        // The view rectangle

    // Immediate data:
    Dimension viewSize = viewBox.getSize();
    int defaultPatchHeight = (int)ceil((float)viewSize.height / nThreads);
    int lastPatchHeight = viewSize.height - (nThreads-1) * defaultPatchHeight;

    // The actual "buffer" is a set of images
    BufferedImage[] images = new BufferedImage[nThreads];

    // ...

    // pseudocode for parallel processing of a for loop
    parallel-for (nThreads, threadId)
    {
        // the starting point and size of this thread's patch
        // handle boundary (last) patch
        int w = viewBox.width;
        int h = threadId == nThread-1 ? lastPatchHeight : defaultPatchHeight;                
        int x = viewBox.x;
        int y = viewBox.y + threadId * defaultPatchHeight;

        BufferedImage patch = new BufferedImage(w, h, BufferedImage.TYPE_INT_ARGB);
        Graphics2D g = off_Image.createGraphics();

        // use g to draw to patch image here
        // better yet: Re-use existing patches and only update the parts that changed.

        images[threadId] = patch;
    }
    return images;
}

// ...

// override paintComponent
@Override
void paintComponent(Graphics gg)
{
    Graphics2D g = (Graphics2D) gg;
    // ...

    // stitch all images together (you can also just display only some images here)
    for (int threadId = 0; threadId < nThreads; ++threadId)
    {
        int w = viewBox.width;
        int h = threadId == nThread-1 ? lastPatchHeight : defaultPatchHeight;                
        int x = viewBox.x;
        int y = viewBox.y + threadId * defaultPatchHeight;

        // use pre-computed images here
        BufferedImage patch = images[threadId];
        g.drawImage(patch, x, y, ...);
    }
}

Answer 2

我想你想要做的是绘制到非UI线程中的缓冲区（所以你管理的那个），并在完成时（在UI线程中）复制缓冲区。