和运算符在else id块中使用时不起作用

Question

i have a block of code, which checks the checked status of checkbox & displays value accordingly, but in my code i have a place where I have to use statement like

if (cb1.isChecked()) {
a="abc";        
} 

else if(cb1.isChecked() && cb2.isChecked()) {
a="pqr";
}

else if(cb2.isChecked()){
a="asd";
}

else{
a="xyz";
}

I get the values if checkbox1 or checkbox2 are selected, but when both the checkboxes are selected i get result as"abc" only

any idea whats wrong with the code??

Answer 1

This is because its an else if instead of if s. Once the first one is satisfied it isn't checking the others. Change the order in which you check these. So something like

if (cb1.isChecked() && cb2.isChecked()) {
    a="abc";        
} 
else if(cb1.isChecked()) {
    a="pqr";
}   
else if(cb2.isChecked()){
    a="asd";
}   
else{
    a="xyz";
}

Answer 2

Modify first if condition to

if(cb1.isChecked() && !cb2.isChecked())

At present, since the first if conditions only depends on value of cb1, so control goes into first block.

Control NEVER goes into the second block in the present logic.

Answer 3

Change to:

if(cb1.isChecked() && cb2.isChecked()) {
a="pqr";
}

else if (cb1.isChecked()) {
a="abc";        
} 

else if(cb2.isChecked()){
a="asd";
}

else{
a="xyz";
}

In your code if cd1 was checked, it would not go into the else anymore.

Answer 4

In an if else ladder, only one block will be executed, you should do this like the following :

if (cb1.isChecked()) {
    a = cb2.isChecked() ? "pqr" : "abc";       
} else if(cb2.isChecked()){
    a="asd";
}
else{
    a="xyz";
}

OR

if(cb1.isChecked() && cb2.isChecked()) {
    a="pqr";
}
else if (cb1.isChecked()) {
    a="abc";        
} 
else if(cb2.isChecked()){
    a="asd";
}
else{
    a="xyz";
}

Answer 5

如果他不是，则使用else进入，如果他不输入其余部分，则进入第一个，仅使用else和user，这样就可以了