如何捕获除特定异常之外的所有异常？

Question

Is it possible to catch all exceptions of a method, except for a specific one, which should be thrown?

void myRoutine() throws SpecificException { 
    try {
        methodThrowingDifferentExceptions();
    } catch (SpecificException) {
        //can I throw this to the next level without eating it up in the last catch block?
    } catch (Exception e) {
        //default routine for all other exceptions
    }
}

/Sidenote: the marked "duplicate" has nothing to do with my question!

Answer 1

void myRoutine() throws SpecificException { 
    try {
        methodThrowingDifferentExceptions();
    } catch (SpecificException se) {
        throw se;
    } catch (Exception e) {
        //default routine for all other exceptions
    }
}

Answer 2

you can do like this

try {
    methodThrowingDifferentExceptions();    
} catch (Exception e) {
    if(e instanceof SpecificException){
      throw e;
    }
}

Answer 3

While other answers are correct, they do not keep the original stack trace. You can use something like this instead:

try
{
  // This throws
  DoSomething();
}
catch(MyException exc)
{
  // This will let the original exception re-throw while keeping it's stack trace
  ExceptionDispatchInfo.Capture(exc).Throw();
  // This will never be called, but is necessary so the compiler does not complain
  // about the fact that the method must return something in every path
  throw;
}
catch(Exception exc)
{
  // This will only be called for other types
  throw new MoreSpecificException("Oops", exc);
}