从URL正则表达式Java中提取数字

Question

I need to extract an last number from an URL followed by a dash.

Example:

http://www.example.com/p-test-test1-a-12345.html

i need to extract the 12345 using regex.

i tried this -\\d(.*?).html which gives me 2345 not sure why it removes 1 any idea?

Answer 1

It removes the first digit as you have invalid pattern it captures everything after -digit

-\\d(.*?).html

-\\d - matches a dash followed by a digit

(.*?) - captures any character (except new line) 0 or more times till next token is satisifed

. - matches any character (except new line)

html - matches html

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Try this pattern:

PATTERN

(?<=-)\d+(?=\.html)

Answer 2

You must add \\d to group: -(\\d.*?).html

if it must be only digits then -(\\d+)\\.html is better.

Answer 3

You're looking for a dash, then a digit, then capturing all characters before ".html", which is why the 1 was not captured.

Try this instead:

-(\\d+)\\.html

Answer 4

Try This :

String pattern2 = ".*?(\\d+)\\.html";
System.out.println(s.replaceAll(pattern2, "$1"));