java中的正则表达式提取了一个数字

Question

i am getting started with regex in java and am trying to extract the number 99999 from a String which looks like:

<result name="response" numFound="99999" start="0">

Can you suggest me what can be the most efficient regex to achieve that? Thanks!

Answer 1

If this is a one-off case, you can use the Pattern and Matcher classes from java.util.regex package as follows and extract the value:

Pattern pattern = Pattern.compile("numFound=\"([0-9]+)\"");
Matcher matcher = pattern.matcher("<result name=\"response\" numFound=\"99999\" start=\"0\">");

if (matcher.find())
{
    System.out.println(matcher.group(1));
}

Otherwise, it is strongly recommended to use a proper HTML Parser like Jericho to parse the HTML and read the attributes accordingly.

Answer 2

Use replaceAll() to extract the part you want in just one line.

String number = input.replaceAll(".*numFound=\"(\\d+).*", "$1");

---

Here's some test code:

public static void main(String[] args) {
    String input = "<result name=\"response\" numFound=\"99999\" start=\"0\">";
    String number = input.replaceAll(".*numFound=\"(\\d+).*", "$1");
    System.out.println(number);
}

Output:

99999