[英]c# Reflection return “Nullable`1”
I define my class, my fields pog_02integer and pog_03smallint are integer that can have null value (int?) 我定义了我的班级,我的字段pog_02integer和pog_03smallint是可以为空值(int?)的整数。
public class v_cCfgDeclaraciones {
public string pog_idcotizacion {get;set;}
public string pog_01varchar {get;set;}
public int? pog_02integer {get;set;}
public int? pog_03smallint {get;set;}
public DateTime? pog_04date {get;set;}
}
How I can return "integer" and not System.DBNull? 如何返回“整数”而不是System.DBNull? I try this, but I can't find a way to return "integer" I just returned System.DBNull if I remove "?"
我尝试了这个,但是我找不到返回“整数”的方法,如果我删除了“?”,我只是返回了System.DBNull。 in the name of the field as a whole recognizes but can't assign a null value.
整个字段名称中的,可以识别但不能分配空值。 I would like to help me resolve this problem, where I can define the field with "?"
我想帮助我解决此问题,我可以在其中定义“?”字段 and I recognize the integer data type and not System.DBNull
而且我知道整数数据类型而不是System.DBNull
foreach (System.Data.DataRow dr in dt.Rows){
object o = Activator.CreateInstance(iSingleType);
foreach (System.Reflection.PropertyInfo Registro in proRegistro){
if ((Registro.PropertyType.Namespace != "System.Collections.Generic") && (AtributoLectura(Registro.GetCustomAttributes(true)))){
TipoDato = Registro.PropertyType.Name;
if (TipoDato == "Nullable`1") {
string v = dr[Registro.Name.ToUpper()].GetType().FullName;
int i = v.IndexOf('.');
int l = v.Length - i;
TipoDato = v.Substring(i, l);
}
switch (TipoDato){
case "Char":
case "String":
break;
case "int": case "integer"
There is a helper method to get a nullable type's underlying value type: Nullable.GetUnderlyingType
. 有一个帮助程序方法可获取可空类型的基础值类型:
Nullable.GetUnderlyingType
。 It will return null if the given type is not a closed over nullable type. 如果给定类型不是可空类型的封闭类型,它将返回null。 I would do something like this:
我会做这样的事情:
Type type = Nullable.GetUnderlyingType(Registro.PropertyType) ?? Registro.PropertyType;
string typeName = type.Name;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.