计算每个成绩在文件中出现的次数

Question

I am trying to print out the number of times each grade appears in a file. 我正在尝试打印每个年级出现在文件中的次数。 score = [89, 45, 67, 78, 98, 0] * This can change for different files, can gain more numbers etc. 分数= [89、45、67、78、98、0] *可以针对不同的文件进行更改，可以获取更多的数字，等等。

low and high scores have already been figured out. 低分数和高分数已经被弄清楚了。 I only need to display the scores between them. 我只需要显示它们之间的分数。 What am I missing? 我想念什么？ It isnt counting the numbers, just printing out this... 它不算数字，只是打印出来...

Any the code is: 任何代码是：

def histogram(score, low, high):
    e = int(low)
    o = int(high)
    for i in range(e, o):
        print(str(i)+": "+str(score.count(i)))
    print()

Answer 1

Not sure if this is what you are looking for. 不知道这是您在寻找什么。 "Frequency of the list" “列表的频率”

import collections
score = [89, 45, 67, 78, 98, 0]
counter=collections.Counter(score)

print(counter)
# Counter({0: 1, 98: 1, 67: 1, 89: 1, 45: 1, 78: 1})

print(counter.most_common())
# [(0, 1), (98, 1), (67, 1), (89, 1), (45, 1), (78, 1)]

Answer 2

Your scores array is a list of strings. 您的成绩数组是一个字符串列表。 Either map it to a list of integers: 要么将其映射到整数列表：

score = map(int, score)

Or count the string value at each step: 或在每个步骤中计算字符串值：

print(str(i)+": "+str(score.count(str(i))))

计算每个成绩在文件中出现的次数

问题描述

2 个解决方案

解决方案1
3 2013-12-05 04:21:18

解决方案2
2 已采纳 2013-12-05 04:23:40

计算每个成绩在文件中出现的次数

问题描述

2 个解决方案

解决方案1 3 2013-12-05 04:21:18

解决方案2 2 已采纳 2013-12-05 04:23:40

解决方案1
3 2013-12-05 04:21:18

解决方案2
2 已采纳 2013-12-05 04:23:40